A(x)=2,4x-0,48x^2

Solution for A(x)=2,4x-0,48x^2 equation:

(A)=2.4A-0.48A^2

We move all terms to the left:

(A)-(2.4A-0.48A^2)=0

We get rid of parentheses

0.48A^2-2.4A+A=0

We add all the numbers together, and all the variables

0.48A^2-1.4A=0

a = 0.48; b = -1.4; c = 0;
Δ = b2-4ac
Δ = -1.42-4·0.48·0
Δ = 1.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$A_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1.4)-\sqrt{1.96}}{2*0.48}=\frac{1.4-\sqrt{1.96}}{0.96}
$
$A_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1.4)+\sqrt{1.96}}{2*0.48}=\frac{1.4+\sqrt{1.96}}{0.96}
$